Percent = per hundred
Thus \(35\%\) means \(35\) parts out of every \(100\) equal parts.
Handwritten-style notes for SSC CGL Tier I and Tier II.
Every percentage question is a comparison against a base of one hundred.
Start with “out of one hundred,” then learn how the changing base controls every advanced problem.
Thus \(35\%\) means \(35\) parts out of every \(100\) equal parts.
It has no unit. The compared quantities must be expressed in compatible units.
“\(20\%\) of \(A\)” uses \(A\) as the base. A change of base changes the percentage even when the absolute difference is unchanged.
Colouring \(37\) cells makes the shaded part \(37\%\). The same idea works even when the actual whole is not \(100\).
Example: \(\frac38\times100\%=37.5\%\).
Move the decimal two places right: \(0.625=62.5\%\).
Always reduce the resulting fraction.
| Fraction | Percentage | Fraction | Percentage |
|---|---|---|---|
| \(\frac12\) | \(50\%\) | \(\frac13\) | \(33\frac13\%\) |
| \(\frac14\) | \(25\%\) | \(\frac15\) | \(20\%\) |
| \(\frac16\) | \(16\frac23\%\) | \(\frac18\) | \(12.5\%\) |
| \(\frac19\) | \(11\frac19\%\) | \(\frac1{10}\) | \(10\%\) |
| \(\frac1{11}\) | \(9\frac1{11}\%\) | \(\frac1{12}\) | \(8\frac13\%\) |
| \(\frac1{16}\) | \(6.25\%\) | \(\frac1{20}\) | \(5\%\) |
| \(\frac1{25}\) | \(4\%\) | \(\frac1{40}\) | \(2.5\%\) |
Percentage and decimal differ by a factor of \(100\). Fraction and percentage connect through multiplication by \(100\%\).
\(18\%\) of \(650\) is \(117\).
\(45\) is \(15\%\) of \(300\).
If \(72\) is \(24\%\), the whole is \(300\).
The old value is always the base.
Increase uses \(+\); decrease uses \(-\).
Do not simply subtract the same percentage from the new value.
An increase and an equal decrease do not cancel because the second move starts from a changed base.
Take decrease as negative if using the universal rule.
Net percentage is \((\text{factor}-1)100\%\).
Convert every change into a multiplier, multiply the multipliers, then compare the result with \(1\). This method works for any number of stages.
After a decrease of \(r\%\), required increase to return is
The visible value is after a multiplier. Divide by that multiplier to travel back to the original; do not reverse by applying the same rate.
The quantity after “than” is the base.
A rate rising from \(20\%\) to \(25\%\) rises by \(5\) percentage points but by
For constant expenditure, price and consumption vary inversely.
Required consumption reduction:
Possible consumption increase:
When a product must remain fixed, replace verbal change with multipliers and make their product \(1\).
| Application | Model | Exam warning |
|---|---|---|
| Population growth | \(P_n=P_0(1+r/100)^n\) | For changing annual rates, multiply distinct yearly factors. |
| Depreciation | \(V_n=V_0(1-r/100)^n\) | Loss is on the reduced value each year. |
| Salary and saving | \(\text{saving}=\text{income}-\text{expenditure}\) | Apply each percentage to its stated base. |
| Marks | \(\text{percentage}=\text{marks obtained}/\text{maximum}\times100\%\) | Pass percentage and obtained percentage may use different statements. |
| Election votes | Convert valid-vote percentages into counts. | Invalid votes are removed before candidate shares if stated so. |
| Percentage error | \(|\text{error}|/|\text{true value}|\times100\%\) | The true/accepted value is the denominator. |
When only percentages matter, let the original be \(100\). This converts rates directly into values.
If two factors change by \(a\%\) and \(b\%\):
Use signs for decreases.
Here \(r\) is decimal change; expand only if useful.
Convert percentages into friendly fractions or multipliers before multiplying large values.
Swap to the easier multiplication. For example, \(4\%\) of \(75\) is easier as \(75\%\) of \(4\).
If the rate is below \(100\%\), its part of a positive whole is smaller than that whole.
Replace successive changes with short factors such as \(1.2\), \(0.8\), \(1.125\), or exact fractions.
Circle “of,” “than,” “original,” “new,” and “valid.” These words reveal the denominator.
Before solving: identify the base, convert change to a multiplier, and estimate the answer range. This eliminates many TCS distractors.
Wrong options usually preserve the arithmetic but silently change the base.
An increase of \(x\%\) followed by a decrease of \(x\%\) gives a net loss of \(x^2/100\%\), because the bases differ.
In “\(A\) is what percent more than \(B\),” divide the difference by \(B\). Reversing the sentence changes the answer.
From \(20\%\) to \(25\%\) is \(5\) percentage points but a \(25\%\) relative increase. TCS options often contain both.
Use a short visual sentence to retrieve the correct base and formula.
Every percent is a fraction whose denominator is \(100\).
Percentage change always divides the difference by the original value.
Turn each change into a factor; multiplying factors automatically respects changing bases.
The new value already contains the multiplier; division recovers the original.
Percentage-point change is simple subtraction; relative percent change divides by the old rate.
If price rises while expenditure stays fixed, consumption must fall by the reciprocal factor.