Ordered comparison
The ratio of \(a\) to \(b\) is
First term: antecedent. Second: consequent.
Handwritten-style notes for SSC CGL Tier I and Tier II.
Ratio compares, proportion equates two ratios, and variation explains how quantities change together.
Learn ratio as an ordered comparison, then build proportion and variation one rule at a time.
The ratio of \(a\) to \(b\) is
First term: antecedent. Second: consequent.
Convert comparable quantities to one unit before forming a ratio.
“Boys to girls” and “girls to boys” are reciprocal comparisons.
Equal-sized objects make the parts visible. If \(6\) blue blocks and \(9\) green blocks are compared, the simplified ratio is \(2:3\), but the total has \(5\) ratio-parts.
Divide all terms by their HCF.
Multiplying or dividing every term by the same non-zero number preserves the ratio.
Multiply every term by the LCM of denominators or a suitable power of \(10\).
For positive denominators:
Scale both ratios until their second terms match; then compare first terms.
Ratio order equals fraction order when consequents are positive.
Cross multiplication avoids decimals. Compare \(ad\) with \(bc\), but keep the denominator signs positive before using the direction of the inequality.
\(a,d\) are extremes; \(b,c\) are means.
If \(a:b=c:x\), then
| Transformation | From \(a/b=c/d\) | Condition / use |
|---|---|---|
| Invertendo | \(b/a=d/c\) | All denominators non-zero. |
| Alternendo | \(a/c=b/d\) | Useful for regrouping corresponding terms. |
| Componendo | \((a+b)/b=(c+d)/d\) | Add denominator to numerator on both sides. |
| Dividendo | \((a-b)/b=(c-d)/d\) | Subtract denominator from numerator. |
| Componendo–dividendo | \((a+b)/(a-b)=(c+d)/(c-d)\) | Requires non-zero new denominators. |
The outer seats are extremes and the inner seats are means. A valid proportion balances when the product of extremes equals the product of means.
Multiply corresponding terms.
For many ratios, multiply all antecedents and all consequents.
To combine \(A:B=a:b\) and \(B:C=c:d\), equalise \(B\).
Scale both ratios until the shared quantity has the same number of parts. Then read all terms in one chain.
If \(Q\) is divided in \(a:b:c\), one part is
Shares are \(ak,bk,ck\).
If shares in \(a:b\) differ by \(D\):
If \(a\) parts equal \(S\), then
Add ratio terms to count total equal parts. Find the value of one part, then multiply by each term. Never divide the quantity by each ratio term separately.
Both move in the same direction by the same factor.
One rises while the other falls.
| Signal language | Likely model | Quick test |
|---|---|---|
| More–more or less–less | Direct proportion | \(y/x\) remains constant. |
| More–less with fixed product | Inverse proportion | \(xy\) remains constant. |
| Varies as product | Joint variation | \(y/(xz)\) remains constant. |
| Varies directly as one and inversely as another | Combined variation | Build a single constant equation first. |
Direction is a clue, not proof. Translate the relation into a constant expression and compare two states.
If \(A:B=a:b\), write
Then apply every stated change to the actual expressions.
Cross multiply and solve for \(k\) or \(x\).
Total remains unchanged; one decreases as the other increases.
Both quantities must remain meaningful and denominators non-zero.
Keep signs attached to their specific quantities; do not alter the ratio terms directly.
| Problem phrase | Fast representation | Core move |
|---|---|---|
| Income : expenditure | \(I:E=a:b\) | Saving is \((a-b)k\), not a ratio term unless converted. |
| Present ages | \(A=ak,B=bk\) | Add/subtract the same number of years, not the same ratio. |
| Two numbers and their sum | \(ak,bk\) | Use \((a+b)k=S\). |
| Two numbers and their difference | \(ak,bk\) | Use \(|a-b|k=D\). |
| Speed and time for fixed distance | \(S\propto1/T\) | Use inverse ratio. |
| Workers and days for fixed work | \(W\propto1/D\) | Use inverse ratio when efficiency is equal. |
Represent unknown amounts as ratio-parts and postpone arithmetic until the final step.
Find the LCM of the two values assigned to the shared quantity, scale both ratios to that value, then combine.
A transfer preserves the total. Equal addition changes the total by twice the addition.
Before solving: match units, preserve order, count total parts, and decide whether the relation is direct or inverse.
Wrong options usually reverse the order, misuse total parts, or confuse direct and inverse change.
From \(A:B=2:3\), you know relative parts, not the actual values. A sum, difference, product or one share is needed to find \(k\).
For a fixed distance, speeds \(2:3\) correspond to times \(3:2\). Copying the same ratio is the standard distractor.
After \(t\) years, ages \(3k,5k\) become \(3k+t,5k+t\), not \(3(k+t),5(k+t)\).
Attach each structural rule to a visual sentence for rapid recall.
Antecedent comes first; reversing the words reciprocates the ratio.
In a proportion, the cross-products of extremes and means are equal.
Both quantities rise or fall by the same factor; their quotient stays fixed.
One rises while the other falls; their product stays fixed.
Add ratio terms, find one part, then multiply to obtain each share.
Equalise the shared term before forming a continued ratio.